Passing an Array Object to a Function in C++

C++ allows you to pass an array to a function by either passing it by value or by reference. Here is how to do each in C++.

Example:

Passing by Value: When passing an array by value, you are creating a new copy of it for the function to use. “`cpp
#include
using namespace std;
void function(int array[], int size)
{
// Our function logic
for(int i = 0; i < size; i++) { cout << array[i] << endl; } } int main() { int array[5]={1,2,3,4,5}; function(array, 5); } ```
Passing by Reference: This means passing the actual array, not a copy. Any changes you perform on the array inside your function will affect the actual array.“`cpp
#include
using namespace std;void function(int* array, int size)
{
// Our function logic
for (int i = 0; i < size; i++) { array[i] = i; } }int main() { int array[5]={1,2,3,4,5}; function(array, 5); for(int i = 0; i < 5; i++) { cout << array[i] << endl; // This will print from 0 to 4 as a result of our function } } ```

Note:

• C++ automatically passes arrays by reference. So you can even avoid using pointers.
• If you want to prohibit your function from modifying the array, you can use the ‘const’ keyword: void function(const int* array, int size).

Remember, practice makes progress. The more you code, the more confident you’ll become. Happy coding!